(3k^2+7k+1)(-2k^2+8k+4)=1

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Solution for (3k^2+7k+1)(-2k^2+8k+4)=1 equation: 



(3k^2+7k+1)(-2k^2+8k+4)=1

We move all terms to the left:

(3k^2+7k+1)(-2k^2+8k+4)-(1)=0

We move all terms containing k to the left, all other terms to the right

(3k^2+7k+1)(-2k^2+8k+4)=1

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